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Date: Sat, 31 Mar 2001 10:01:33 +1000
To: <bgilmore@at*.ne*>, techdiver@aquanaut.com
From: Bruce Stewart <bruces@sh*.ne*.au*>
Subject: Re: altitude barometric correction
Brad,

if the below is correct theres zero pressure at the summit
of Everest!=20

B



At 11:01 AM 3/30/01 -0800, bgilmore@at*.ne* wrote:
>For a back of envelope calculation
>
>Atmospheric pressure drops approximately 1 inHg per 1,000 ft. of rise in=20
>elevation. Sea level atmospheric pressure is 29.92 inHg
>
>For example:
>Diving at a lake with an elevation of 3150=92 MSL
>3150 ft  =3D 3.15 inHg=20
>Therefore, the correction factor will be:
>(29.92 =AD 3.15)/ 29.92 =3D .895
>And
>...895 * 14.7 psia =3D 13.1 psia
>...895 * 1013 mBar =3D 907 mBar
>
>This is good enough for Decoplanner.
>
>Brad
>
>
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