Brad, if the below is correct theres zero pressure at the summit of Everest!=20 B At 11:01 AM 3/30/01 -0800, bgilmore@at*.ne* wrote: >For a back of envelope calculation > >Atmospheric pressure drops approximately 1 inHg per 1,000 ft. of rise in=20 >elevation. Sea level atmospheric pressure is 29.92 inHg > >For example: >Diving at a lake with an elevation of 3150=92 MSL >3150 ft =3D 3.15 inHg=20 >Therefore, the correction factor will be: >(29.92 =AD 3.15)/ 29.92 =3D .895 >And >...895 * 14.7 psia =3D 13.1 psia >...895 * 1013 mBar =3D 907 mBar > >This is good enough for Decoplanner. > >Brad > > >-- >Send mail for the `techdiver' mailing list to `techdiver@aquanaut.com'. >Send subscribe/unsubscribe requests to `techdiver-request@aquanaut.com'. -- Send mail for the `techdiver' mailing list to `techdiver@aquanaut.com'. Send subscribe/unsubscribe requests to `techdiver-request@aquanaut.com'.
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