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Date: Sat, 21 Oct 2000 21:05:01 -0400
To: Paul Braunbehrens <Bakalite@ba*.co*>
From: Mike Rodriguez <mikey@ma*.co*>
Subject: RE: Pony's and deep air
Cc: "Todd Baldi" <todd_baldi@ho*.co*>, trey@ne*.co*,
At 05:35 PM 10/21/2000 -0700, Paul Braunbehrens wrote:

Hello Paul,

>However, if it takes 1/2 hour in water to cool your tank

It doesn't take that long...

>and 4 hours in air, and they fill your 
>tank in 5 minutes and then take it out of the water, then the water 
>isn't doing much.

Even in those five minutes a significant amount of thermal energy
can be transferred from the tank to the water.  The rate at which
the energy moves from one to the other is a function of the
temperature differential.  The temperature drop, like many things
in nature, is a curve, not a line.  When the tank is at its hottest,
the energy is leaving at the fastest rate (steep end of the curve).  So,
five minutes right after a hot fill does a lot more for you than five
minutes when the tanks are close to equilibrium.

>The question is if it has any effect in the real world 
>situation of getting a fill.

OK, I see where you're coming from.  I don't work in a dive shop and
never have, so I can't say whether at a rapid-fire fill station water
makes any difference (though most fill-stations have water so that
should tell you something).  I do, however, fill two to four sets
of doubles plus deco bottles and stages for myself every weekend.
In that scenario the water makes a huge difference.

-Mike Rodriguez
<mikey@mi*.ne*>
http://www.mikey.net/aue
Pn(x) = (1/(2^n)n!)[d/dx]^n(x^2 - 1)^n

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