OK, I'll bite. The absolute pressure at 245 feet is approximately: 245/33 + 1 = 8.4ATM Assuming an IP of 150PSI, the regulator will stop delivering air somwhere around: 8.4 x 14.7 + 150 = 275PSI Assuming linear compression of the gas, and a luxfer Al80, the gas available in the drop from 1200 to 275PSI is: (1200 - 275)/3000 * 77.4 = 23.9cuft Given a surface consumption of .7 cuft/min, gas consumption at depth would be: 8.4 x 0.7cuft/min = 5.9cuft/min Looks to me to be about 4 minutes. Personally, I would be tempted to add a safety factor. That was fun, I actually got to use my calculator today. Cheers David In message "Formula", bcolman@gt*.ne* writes: > =09 > Can anyone help me out... > > At 245 FSW, there is 1200 PSI in a 80Cu.Ft Cylinder, if the divers > gas consumption is .7ft/min, how long will it last..?? I cant seem > to find the right formula..?? > =20 > -- > Send mail for the `techdiver' mailing list to `techdiver@aquanaut.com'. > Send subscribe/unsubscribe requests to `techdiver-request@aquanaut.com'. > -- Send mail for the `techdiver' mailing list to `techdiver@aquanaut.com'. Send subscribe/unsubscribe requests to `techdiver-request@aquanaut.com'.
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