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On Thu, 7 Jul 1994 ddoolett@me*.ad*.ed*.au* wrote: > this figure of 1 litre nitrogen/bar at saturation seems about right, > presuming it means 1 bar air saturation. You can get a rough feel > for this by multiplying bogy weight in kilograms by nitrogen solubility. > Lets say the the body is 80% water and 20% fat (actually more like > 72% water, 18% fat, 10% puppy dog tails in males) and the respective > solubilities for nitrogen are 0.012ml/ml/bar and 0.052ml/ml/bar. This > gives a combined "body solubility of 0.02ml/ml/bar. Assume a 70kg body > weight and this being mostly water is approximately 70 litres. > 0.02ml/ml/bar X 70,000ml X 0.8bar = 1.12 litres nitrogen at saturation. > This also seems to be roughly equal to the amount of nitrogen offgassed > with isobaric inert gas change after saturation in the paper I mentioned > in my previous post. Of course you would need to know how saturated you > are and this would require working out a whole body half-time for gas > uptake and elimination, how about 30 minutes-just a guess!!! AHHH!!!! Finally some real data on this question! Thank you! In terms of figuring out how much dissolved gas at susb-saturation exposures, it seems to me you'd need to know the propotional volume (within a diver) of the different tissues represented by the different half-time compartments. In other words, if we're composed mostly of "slowish" tissues, then the curve of total dissolved gas volume over time would be different from the curve if most of our volume is fastish tissues. And I'm sure the proportion of slowish:fastish tissues varies between individuals. Seems to me a difficult thing to calculate - even for a computer... Aloha, Rich
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