> Now, add two more identical computers, any one of which can fully operate > the system. The computer complexity has just increased by a factor of 3, > so the probability of a component failure has tripled. However, since 3 > simultaneous computer failures are required to bring the whole system > down, the probability of a system failure is the cube root of the > probability of a single computer failure (i.e., MUCH less -- assuming the > three computers are truly independant entities). Golly, Batman- do you suppose that could apply to SCUBA sets, too?
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