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<eku4833380@ao*.co*> writes: > How to figure out how much weight a 410# fully equiped diver(no lead) > needs for diving in salt water (64#-cf) or fresh 62.4#-cf)??????I think i > screwed it up > a diver 410# displaces 6.40 cf of water 410 divided by 64= 6.40 ( in sea > water) 6.40 X64# ( what a cf of sea water weighs ) = 410# so the diver is > nutral .Its wrong though > When i tried it with my weight 15# i still wound up with 425# for the > answer . That formula won't tell you how much lead you need if you haven't been in the water yet. If perchance you did know your displacement, then you could figure out directly what total all-up weight would actually be neutral in fresh or in salt, and therefore how much lead to add to you and the rest of your gear. Normally you'd figure out your weight by trial-and-error in shallow water with fairly-empty tanks; with experience, divers often shed a few pounds. A lot of that can be attributed to getting to be relaxed enough in the water to fully exhale each breath. Where those numbers do come in handy is if you've been diving already in one kind of water and you're about to go visit the other kind. For example, if you weigh 410 pounds set up to dive in fresh water, with tanks and an appropriate weight belt and everything, then 410/62.4 is your displacement of 6.57 cubic feet; multiply that by 64.0 to get 420.48 pounds that you have to weigh to be neutral in salt. I'd throw on another 10 pounds. On the other hand, if a config totalling 410 pounds had you neutral in salt, then 410/64 tells you you displace 6.4 cubic feet, and 6.4*62.4 is 399.36 pounds in fresh, so you want to shed about 11 pounds of lead. -- Anthony DeBoer <adb@on*.ca*> -- Send mail for the `techdiver' mailing list to `techdiver@aquanaut.com'. Send subscribe/unsubscribe requests to `techdiver-request@aquanaut.com'.
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