>>And the saga continues... (g) >> >>>Scott, >>> >>>Let me check, but I do not think that the statement: >>> >>>>4) CO binding is so thermodynamically favorable that binding is, >>>>practically speaking, permanent, essentially removing the bound >>>>hemo site from the pool of available transport. >>> >>>is quite accurate. At sealevel, with only 0.21 ATA of oxygen partial >>>pressure, this statement is essentially true, but in the presence of >>>high enough partial pressures of oxygen, monoxide will unbind from >>>hemoglobin. "Further more, it bind with about 230 times as much tenacity >>>as oxygen, which is illustrated by the carbon monoxide-hemoglobin >>>dissociation curve in Figure 41-12 (this is take from Guyton's "Textbook >>>of Medical Physiology", page 511 and 512). This curve is almost identical >>>with the oxygen-hemoglobin dissociation curve, except that the pressures >>>of the carbon monoxide shown on the abscissa are at a level 1/230 of those >>>on the oxygen dissociation curve. Therefore, a carbon monoxide pressure >>>of only 0.4 torr in the alveoli, 1/230 that of the alveolar oxygen, allows >>>the carbon moxide to COMPETE equally wit# the hemoglobin and causes half to >>>the hemoglobin in the blood to become bound with monoxide instead of >>oxgyen." >> >>Aren't we really saying the same thing? That ratio adds up to an >>overwhelming thermodynamic favorability for the CO binding over O2 >>in my book. And, barring administration of unusual and artificial >>driving forces to that reaction, the hemoglobin would certainly >>remain bound for the servicable lifetime of the molecule. >>Unusual and artificial driving forces such as high-pressure >>O2, aka one treatment for CO posioning. >> > >carboxyhaemoglobin half-life in air is about 5.5 hours > >regards, > >David Doolette >ddoolett@me*.ad*.ed*.au* > Facinating. I'll double check with my source, and thanks. ------------------------------------------------------- scot@bt*.co* Scot Anderson pp000082@in*.co* Voice: 703/761/6536 CIS:74147.2357 Fax: 703/556/9290
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