Mike, anyone who has a 14 k modem probably has a rig
like that, so can just delete the picture from the
server.

Otherwise, I went to Little River this weekend and
Ginnie with TC, Cameron and Pina. I was up in High
Springs helping JJ with his new book. What I
observed is that the gear rigs are getting better ,
at least I did not see any stuffed hoses, but the
butt mounting is still going on , and the skill
level of the divers is so piss poor that it hurts to
watch them dive.

I don't know what these people are thinking, but
they really suck.

The only two guys I saw who were not floundering all
over the place were Lamar Hires and Hogarthian Harry
Averil, but then of course Lamar you could see a
mile away by the yellow boxes on his arms. Some kind
of video game or something.

-----Original Message-----
From: Mike Rodriguez <mikey@ma*.co*>
To: Scott Landon <js_landon@ho*.co*>
Cc: jammer@oz*.ne* <jammer@oz*.ne*>;
Ivanic@di*.ne*
<Ivanic@di*.ne*>; cavers@cavers.com
<cavers@cavers.com>
Date: Tuesday, September 05, 2000 8:04 PM
Subject: Re: [Fwd: cave rig pic]


>At 01:10 PM 9/5/2000 GMT, Scott Landon wrote:
>
>>haha - i logged in from work with a T1 connection.
took me just a sec to
>>read it.  those pictures were worth it.
>
>Guys, while most of us in the US are lucky to have
access to T1s,
>DSL, and Cable-Modems, there are people on this
list from other
>parts of the world where Internet access is by
14.4kbps modem and
>paid for BY THE MINUTE.
>
>It's extremely rude, insensitive, and inconsiderate
to force-feed
>someone a binary attachment, especially a large
one.  Doing so makes
>the sender no better than a spammer.
>
>If you MUST share a binary attachment with the
list, put it on a
>web site (you can get one for free, you know) and
send the list the
>URL to the site.  That way the people who want the
attachment can go
>get it while those who don't can delete the message
without spending
>a lot of time and money downloading it.
>
>This is simply basic netiquette.
>
>-Mike Rodriguez
><mikey@mi*.ne*>
>http://www.mikey.net/aue
>Pn(x) = (1/(2^n)n!)[d/dx]^n(x^2 - 1)^n
>

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